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fix(curriculum): correct typo in step 12 (#64481)

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Co-authored-by: Huyen Nguyen <25715018+huyenltnguyen@users.noreply.github.com>
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shaharyosef
2025-12-11 09:01:53 +01:00
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co-authored by Huyen Nguyen
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curriculum/challenges/english/blocks/workshop-decimal-to-binary-converter/64007367d54d2a7efbf44fcf.md
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@@ -19,7 +19,7 @@ isNaN("3.5"); // false
Update the second condition in your `if` statement to use the `isNaN()` function to check if the value returned by `parseInt()` is `NaN`.
Also,as we mentioned in step 1 that we are considering only positive numbers, we should add a third condition in `if` statement to check whether the number is less than 0 (i.e negative numbers)
Also, as we mentioned in step 1, we are considering only positive numbers, so we should add a third condition to the `if` statement to check whether the number is less than 0 (i.e., negative numbers).
```js
6 < 0; // false