From 66c31e1071440d24730d56aac3007f3ff879c527 Mon Sep 17 00:00:00 2001
From: shaharyosef <156474969+shaharyosef@users.noreply.github.com>
Date: Thu, 11 Dec 2025 10:01:53 +0200
Subject: [PATCH] fix(curriculum): correct typo in step 12 (#64481)

Co-authored-by: Huyen Nguyen <25715018+huyenltnguyen@users.noreply.github.com>
---
 .../64007367d54d2a7efbf44fcf.md                                 | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/curriculum/challenges/english/blocks/workshop-decimal-to-binary-converter/64007367d54d2a7efbf44fcf.md b/curriculum/challenges/english/blocks/workshop-decimal-to-binary-converter/64007367d54d2a7efbf44fcf.md
index 83a95d8f8f0..f864e92fb62 100644
--- a/curriculum/challenges/english/blocks/workshop-decimal-to-binary-converter/64007367d54d2a7efbf44fcf.md
+++ b/curriculum/challenges/english/blocks/workshop-decimal-to-binary-converter/64007367d54d2a7efbf44fcf.md
@@ -19,7 +19,7 @@ isNaN("3.5"); // false
 
 Update the second condition in your `if` statement to use the `isNaN()` function to check if the value returned by `parseInt()` is `NaN`.
 
-Also,as we mentioned in step 1 that we are considering only positive numbers, we should add a third condition in `if` statement to check whether the number is less than 0 (i.e negative numbers)
+Also, as we mentioned in step 1, we are considering only positive numbers, so we should add a third condition to the `if` statement to check whether the number is less than 0 (i.e., negative numbers).
 
 ```js
  6 < 0; // false