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- Remove overlap between bboxes for block separation - Sort bboxes by combined x and y coordinates for better layout handling - Comment out previous overlap removal function
258 lines
9.1 KiB
Python
258 lines
9.1 KiB
Python
from magic_pdf.config.ocr_content_type import BlockType
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from magic_pdf.libs.boxbase import (
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calculate_iou,
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calculate_overlap_area_in_bbox1_area_ratio,
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calculate_vertical_projection_overlap_ratio,
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get_minbox_if_overlap_by_ratio
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)
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from magic_pdf.pre_proc.remove_bbox_overlap import remove_overlap_between_bbox_for_block
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def add_bboxes(blocks, block_type, bboxes):
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for block in blocks:
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x0, y0, x1, y1 = block['bbox']
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if block_type in [
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BlockType.ImageBody,
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BlockType.ImageCaption,
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BlockType.ImageFootnote,
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BlockType.TableBody,
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BlockType.TableCaption,
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BlockType.TableFootnote,
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]:
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bboxes.append(
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[
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x0,
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y0,
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x1,
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y1,
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None,
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None,
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None,
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block_type,
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None,
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None,
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None,
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None,
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block['score'],
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block['group_id'],
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]
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)
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else:
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bboxes.append(
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[
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x0,
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y0,
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x1,
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y1,
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None,
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None,
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None,
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block_type,
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None,
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None,
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None,
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None,
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block['score'],
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]
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)
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def ocr_prepare_bboxes_for_layout_split_v2(
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img_body_blocks,
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img_caption_blocks,
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img_footnote_blocks,
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table_body_blocks,
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table_caption_blocks,
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table_footnote_blocks,
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discarded_blocks,
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text_blocks,
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title_blocks,
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interline_equation_blocks,
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page_w,
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page_h,
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):
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all_bboxes = []
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add_bboxes(img_body_blocks, BlockType.ImageBody, all_bboxes)
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add_bboxes(img_caption_blocks, BlockType.ImageCaption, all_bboxes)
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add_bboxes(img_footnote_blocks, BlockType.ImageFootnote, all_bboxes)
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add_bboxes(table_body_blocks, BlockType.TableBody, all_bboxes)
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add_bboxes(table_caption_blocks, BlockType.TableCaption, all_bboxes)
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add_bboxes(table_footnote_blocks, BlockType.TableFootnote, all_bboxes)
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add_bboxes(text_blocks, BlockType.Text, all_bboxes)
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add_bboxes(title_blocks, BlockType.Title, all_bboxes)
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add_bboxes(interline_equation_blocks, BlockType.InterlineEquation, all_bboxes)
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"""block嵌套问题解决"""
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"""文本框与标题框重叠,优先信任文本框"""
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all_bboxes = fix_text_overlap_title_blocks(all_bboxes)
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"""任何框体与舍弃框重叠,优先信任舍弃框"""
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all_bboxes = remove_need_drop_blocks(all_bboxes, discarded_blocks)
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# interline_equation 与title或text框冲突的情况,分两种情况处理
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"""interline_equation框与文本类型框iou比较接近1的时候,信任行间公式框"""
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all_bboxes = fix_interline_equation_overlap_text_blocks_with_hi_iou(all_bboxes)
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"""interline_equation框被包含在文本类型框内,且interline_equation比文本区块小很多时信任文本框,这时需要舍弃公式框"""
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# 通过后续大框套小框逻辑删除
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"""discarded_blocks"""
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all_discarded_blocks = []
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add_bboxes(discarded_blocks, BlockType.Discarded, all_discarded_blocks)
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"""footnote识别:宽度超过1/3页面宽度的,高度超过10的,处于页面下半50%区域的"""
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footnote_blocks = []
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for discarded in discarded_blocks:
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x0, y0, x1, y1 = discarded['bbox']
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if (x1 - x0) > (page_w / 3) and (y1 - y0) > 10 and y0 > (page_h / 2):
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footnote_blocks.append([x0, y0, x1, y1])
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"""移除在footnote下面的任何框"""
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need_remove_blocks = find_blocks_under_footnote(all_bboxes, footnote_blocks)
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if len(need_remove_blocks) > 0:
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for block in need_remove_blocks:
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all_bboxes.remove(block)
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all_discarded_blocks.append(block)
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"""经过以上处理后,还存在大框套小框的情况,则删除小框"""
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all_bboxes = remove_overlaps_min_blocks(all_bboxes)
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all_discarded_blocks = remove_overlaps_min_blocks(all_discarded_blocks)
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"""将剩余的bbox做分离处理,防止后面分layout时出错"""
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# all_bboxes, drop_reasons = remove_overlap_between_bbox_for_block(all_bboxes)
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all_bboxes.sort(key=lambda x: x[0]+x[1])
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return all_bboxes, all_discarded_blocks
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def find_blocks_under_footnote(all_bboxes, footnote_blocks):
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need_remove_blocks = []
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for block in all_bboxes:
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block_x0, block_y0, block_x1, block_y1 = block[:4]
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for footnote_bbox in footnote_blocks:
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footnote_x0, footnote_y0, footnote_x1, footnote_y1 = footnote_bbox
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# 如果footnote的纵向投影覆盖了block的纵向投影的80%且block的y0大于等于footnote的y1
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if (
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block_y0 >= footnote_y1
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and calculate_vertical_projection_overlap_ratio(
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(block_x0, block_y0, block_x1, block_y1), footnote_bbox
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)
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>= 0.8
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):
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if block not in need_remove_blocks:
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need_remove_blocks.append(block)
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break
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return need_remove_blocks
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def fix_interline_equation_overlap_text_blocks_with_hi_iou(all_bboxes):
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# 先提取所有text和interline block
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text_blocks = []
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for block in all_bboxes:
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if block[7] == BlockType.Text:
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text_blocks.append(block)
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interline_equation_blocks = []
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for block in all_bboxes:
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if block[7] == BlockType.InterlineEquation:
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interline_equation_blocks.append(block)
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need_remove = []
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for interline_equation_block in interline_equation_blocks:
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for text_block in text_blocks:
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interline_equation_block_bbox = interline_equation_block[:4]
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text_block_bbox = text_block[:4]
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if calculate_iou(interline_equation_block_bbox, text_block_bbox) > 0.8:
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if text_block not in need_remove:
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need_remove.append(text_block)
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if len(need_remove) > 0:
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for block in need_remove:
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all_bboxes.remove(block)
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return all_bboxes
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def fix_text_overlap_title_blocks(all_bboxes):
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# 先提取所有text和title block
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text_blocks = []
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for block in all_bboxes:
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if block[7] == BlockType.Text:
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text_blocks.append(block)
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title_blocks = []
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for block in all_bboxes:
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if block[7] == BlockType.Title:
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title_blocks.append(block)
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need_remove = []
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for text_block in text_blocks:
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for title_block in title_blocks:
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text_block_bbox = text_block[:4]
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title_block_bbox = title_block[:4]
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if calculate_iou(text_block_bbox, title_block_bbox) > 0.8:
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if title_block not in need_remove:
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need_remove.append(title_block)
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if len(need_remove) > 0:
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for block in need_remove:
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all_bboxes.remove(block)
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return all_bboxes
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def remove_need_drop_blocks(all_bboxes, discarded_blocks):
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need_remove = []
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for block in all_bboxes:
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for discarded_block in discarded_blocks:
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block_bbox = block[:4]
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if (
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calculate_overlap_area_in_bbox1_area_ratio(
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block_bbox, discarded_block['bbox']
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)
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> 0.6
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):
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if block not in need_remove:
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need_remove.append(block)
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break
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if len(need_remove) > 0:
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for block in need_remove:
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all_bboxes.remove(block)
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return all_bboxes
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def remove_overlaps_min_blocks(all_bboxes):
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# 重叠block,小的不能直接删除,需要和大的那个合并成一个更大的。
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# 删除重叠blocks中较小的那些
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need_remove = []
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for block1 in all_bboxes:
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for block2 in all_bboxes:
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if block1 != block2:
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block1_bbox = block1[:4]
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block2_bbox = block2[:4]
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overlap_box = get_minbox_if_overlap_by_ratio(
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block1_bbox, block2_bbox, 0.8
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)
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if overlap_box is not None:
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block_to_remove = next(
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(block for block in all_bboxes if block[:4] == overlap_box),
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None,
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)
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if (
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block_to_remove is not None
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and block_to_remove not in need_remove
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):
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large_block = block1 if block1 != block_to_remove else block2
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x1, y1, x2, y2 = large_block[:4]
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sx1, sy1, sx2, sy2 = block_to_remove[:4]
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x1 = min(x1, sx1)
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y1 = min(y1, sy1)
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x2 = max(x2, sx2)
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y2 = max(y2, sy2)
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large_block[:4] = [x1, y1, x2, y2]
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need_remove.append(block_to_remove)
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if len(need_remove) > 0:
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for block in need_remove:
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all_bboxes.remove(block)
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return all_bboxes
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